You can post your problem related to Chemical Projects here. We will try our best to help you out.
- Posts: 16
- Joined: Wed Mar 01, 2017 11:23 am
I've found the value for K using Gibbs free-energy values (in KJ/mol) where Gibbs free-energy = -5.707*log(K).
Would that mean the units of K are KJ/mol as well?